1012013407 has 2 divisors, whose sum is σ = 1012013408. Its totient is φ = 1012013406.

The previous prime is 1012013399. The next prime is 1012013411. The reversal of 1012013407 is 7043102101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1012013407 - 2³ = 1012013399 is a prime.

It is a super-2 number, since 2×1012013407² = 2048342271895495298, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012013467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006703 + 506006704.

It is an arithmetic number, because the mean of its divisors is an integer number (506006704).

Almost surely, 2^1012013407 is an apocalyptic number.

1012013407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012013407 is an equidigital number, since it uses as much as digits as its factorization.

1012013407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 19.

The square root of 1012013407 is about 31812.1581631929. The cubic root of 1012013407 is about 1003.9885394029.

Adding to 1012013407 its reverse (7043102101), we get a palindrome (8055115508).

The spelling of 1012013407 in words is "one billion, twelve million, thirteen thousand, four hundred seven".