Base | Representation |
---|---|
bin | 10111000000101011101110… |
… | …011101011001011010010011 |
3 | 111021022211002210012221222211 |
4 | 113000223232131121122103 |
5 | 101231043214122041034 |
6 | 555123322145212551 |
7 | 30213414254413561 |
oct | 2700535635313223 |
9 | 437284083187884 |
10 | 101202020112019 |
11 | 2a278599027332 |
12 | b425767931157 |
13 | 44614040ca3b8 |
14 | 1adc2bd74ca31 |
15 | ba776b9e1d64 |
hex | 5c0aee759693 |
101202020112019 has 2 divisors, whose sum is σ = 101202020112020. Its totient is φ = 101202020112018.
The previous prime is 101202020111989. The next prime is 101202020112041. The reversal of 101202020112019 is 910211020202101.
It is an a-pointer prime, because the next prime (101202020112041) can be obtained adding 101202020112019 to its sum of digits (22).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101202020112019 - 25 = 101202020111987 is a prime.
It is a super-2 number, since 2×1012020201120192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101202020152019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50601010056009 + 50601010056010.
It is an arithmetic number, because the mean of its divisors is an integer number (50601010056010).
Almost surely, 2101202020112019 is an apocalyptic number.
101202020112019 is a deficient number, since it is larger than the sum of its proper divisors (1).
101202020112019 is an equidigital number, since it uses as much as digits as its factorization.
101202020112019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 22.
The spelling of 101202020112019 in words is "one hundred one trillion, two hundred two billion, twenty million, one hundred twelve thousand, nineteen".
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