Base | Representation |
---|---|
bin | 11101011101000010010… |
… | …10100110101010010011 |
3 | 10120202012111110222121111 |
4 | 32232201022212222103 |
5 | 113040104413214011 |
6 | 2052525515034151 |
7 | 133054554326356 |
oct | 16564112465223 |
9 | 3522174428544 |
10 | 1012021226131 |
11 | 360217665023 |
12 | 144177a3b957 |
13 | 745829528b6 |
14 | 36da6bcc29d |
15 | 1b4d1ccb121 |
hex | eba12a6a93 |
1012021226131 has 2 divisors, whose sum is σ = 1012021226132. Its totient is φ = 1012021226130.
The previous prime is 1012021226129. The next prime is 1012021226189. The reversal of 1012021226131 is 1316221202101.
1012021226131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1012021226131 - 21 = 1012021226129 is a prime.
It is a super-2 number, since 2×10120212261312 (a number of 25 digits) contains 22 as substring.
Together with 1012021226129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1012021226191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506010613065 + 506010613066.
It is an arithmetic number, because the mean of its divisors is an integer number (506010613066).
Almost surely, 21012021226131 is an apocalyptic number.
1012021226131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012021226131 is an equidigital number, since it uses as much as digits as its factorization.
1012021226131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 1012021226131 its reverse (1316221202101), we get a palindrome (2328242428232).
The spelling of 1012021226131 in words is "one trillion, twelve billion, twenty-one million, two hundred twenty-six thousand, one hundred thirty-one".
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