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101202202202102 = 250601101101051
BaseRepresentation
bin10111000000101011111001…
…010100000000111111110110
3111021022211120110212002121222
4113000223321110000333312
5101231044102230431402
6555123352212110342
730213421625225501
oct2700537124007766
9437284513762558
10101202202202102
112a278681897301
12b4257b89053b2
134461432a53701
141adc2d99cc138
15ba777c9ae7a2
hex5c0af9500ff6

101202202202102 has 4 divisors (see below), whose sum is σ = 151803303303156. Its totient is φ = 50601101101050.

The previous prime is 101202202202069. The next prime is 101202202202111. The reversal of 101202202202102 is 201202202202101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25300550550524 + ... + 25300550550527.

It is an arithmetic number, because the mean of its divisors is an integer number (37950825825789).

Almost surely, 2101202202202102 is an apocalyptic number.

101202202202102 is a deficient number, since it is larger than the sum of its proper divisors (50601101101054).

101202202202102 is an equidigital number, since it uses as much as digits as its factorization.

101202202202102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50601101101053.

The product of its (nonzero) digits is 128, while the sum is 17.

Adding to 101202202202102 its reverse (201202202202101), we get a palindrome (302404404404203).

Subtracting 101202202202102 from its reverse (201202202202101), we obtain a palindrome (99999999999999).

The spelling of 101202202202102 in words is "one hundred one trillion, two hundred two billion, two hundred two million, two hundred two thousand, one hundred two".

Divisors: 1 2 50601101101051 101202202202102