1012022111011 has 2 divisors, whose sum is σ = 1012022111012. Its totient is φ = 1012022111010.

The previous prime is 1012022110907. The next prime is 1012022111053. The reversal of 1012022111011 is 1101112202101.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (1101112202101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1012022111011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1012022110982 and 1012022111000.

It is not a weakly prime, because it can be changed into another prime (1012322111011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506011055505 + 506011055506.

It is an arithmetic number, because the mean of its divisors is an integer number (506011055506).

Almost surely, 2^{1012022111011} is an apocalyptic number.

1012022111011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012022111011 is an equidigital number, since it uses as much as digits as its factorization.

1012022111011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 1012022111011 its reverse (1101112202101), we get a palindrome (2113134313112).

The spelling of 1012022111011 in words is "one trillion, twelve billion, twenty-two million, one hundred eleven thousand, eleven".