Base | Representation |
---|---|
bin | 11101011101000011011… |
… | …11111000111011110111 |
3 | 10120202020011212120021011 |
4 | 32232201233320323313 |
5 | 113040114414002221 |
6 | 2052530504333051 |
7 | 133055033365462 |
oct | 16564157707367 |
9 | 3522204776234 |
10 | 1012031000311 |
11 | 360222130561 |
12 | 14417b174187 |
13 | 74584995736 |
14 | 36da82142d9 |
15 | 1b4d2aac1e1 |
hex | eba1bf8ef7 |
1012031000311 has 2 divisors, whose sum is σ = 1012031000312. Its totient is φ = 1012031000310.
The previous prime is 1012031000303. The next prime is 1012031000317. The reversal of 1012031000311 is 1130001302101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1012031000311 - 23 = 1012031000303 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1012031000291 and 1012031000300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012031000317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506015500155 + 506015500156.
It is an arithmetic number, because the mean of its divisors is an integer number (506015500156).
Almost surely, 21012031000311 is an apocalyptic number.
1012031000311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012031000311 is an equidigital number, since it uses as much as digits as its factorization.
1012031000311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1012031000311 its reverse (1130001302101), we get a palindrome (2142032302412).
The spelling of 1012031000311 in words is "one trillion, twelve billion, thirty-one million, three hundred eleven", and thus it is an aban number.
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