Base | Representation |
---|---|
bin | 10010110110011011… |
… | …11010110100100011 |
3 | 222010022011000111012 |
4 | 21123031322310203 |
5 | 131211244410201 |
6 | 4352121211135 |
7 | 505535134055 |
oct | 113315726443 |
9 | 28108130435 |
10 | 10120310051 |
11 | 4323718805 |
12 | 1b65330aab |
13 | c538c2557 |
14 | 6c011d8d5 |
15 | 3e37255bb |
hex | 25b37ad23 |
10120310051 has 2 divisors, whose sum is σ = 10120310052. Its totient is φ = 10120310050.
The previous prime is 10120310047. The next prime is 10120310111. The reversal of 10120310051 is 15001302101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10120310051 - 22 = 10120310047 is a prime.
It is not a weakly prime, because it can be changed into another prime (10120312051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060155025 + 5060155026.
It is an arithmetic number, because the mean of its divisors is an integer number (5060155026).
Almost surely, 210120310051 is an apocalyptic number.
10120310051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120310051 is an equidigital number, since it uses as much as digits as its factorization.
10120310051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30, while the sum is 14.
Adding to 10120310051 its reverse (15001302101), we get a palindrome (25121612152).
The spelling of 10120310051 in words is "ten billion, one hundred twenty million, three hundred ten thousand, fifty-one".
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