Base | Representation |
---|---|
bin | 11101011101000011100… |
… | …01011101010001101111 |
3 | 10120202020012122110001101 |
4 | 32232201301131101233 |
5 | 113040120020130221 |
6 | 2052530521223531 |
7 | 133055040026644 |
oct | 16564161352157 |
9 | 3522205573041 |
10 | 1012031411311 |
11 | 360222391328 |
12 | 14417b331ba7 |
13 | 74584aaa82b |
14 | 36da82bddcb |
15 | 1b4d2b3dd91 |
hex | eba1c5d46f |
1012031411311 has 2 divisors, whose sum is σ = 1012031411312. Its totient is φ = 1012031411310.
The previous prime is 1012031411273. The next prime is 1012031411441. The reversal of 1012031411311 is 1131141302101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1012031411311 - 29 = 1012031410799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012031412311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506015705655 + 506015705656.
It is an arithmetic number, because the mean of its divisors is an integer number (506015705656).
Almost surely, 21012031411311 is an apocalyptic number.
1012031411311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012031411311 is an equidigital number, since it uses as much as digits as its factorization.
1012031411311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1012031411311 its reverse (1131141302101), we get a palindrome (2143172713412).
The spelling of 1012031411311 in words is "one trillion, twelve billion, thirty-one million, four hundred eleven thousand, three hundred eleven".
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