Base | Representation |
---|---|
bin | 101111001000000110… |
… | …0000011000000000011 |
3 | 100200020000220120201202 |
4 | 1132100030003000003 |
5 | 3124231022344211 |
6 | 114254150251415 |
7 | 10211625032312 |
oct | 1362014030003 |
9 | 320200816652 |
10 | 101203324931 |
11 | 39a13702a15 |
12 | 17744956b6b |
13 | 970abc9427 |
14 | 4c80bb8279 |
15 | 2974bd053b |
hex | 1790303003 |
101203324931 has 2 divisors, whose sum is σ = 101203324932. Its totient is φ = 101203324930.
The previous prime is 101203324927. The next prime is 101203324933. The reversal of 101203324931 is 139423302101.
It is a strong prime.
It is an emirp because it is prime and its reverse (139423302101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101203324931 - 22 = 101203324927 is a prime.
It is a super-2 number, since 2×1012033249312 (a number of 23 digits) contains 22 as substring.
Together with 101203324933, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 101203324894 and 101203324903.
It is not a weakly prime, because it can be changed into another prime (101203324933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50601662465 + 50601662466.
It is an arithmetic number, because the mean of its divisors is an integer number (50601662466).
Almost surely, 2101203324931 is an apocalyptic number.
101203324931 is a deficient number, since it is larger than the sum of its proper divisors (1).
101203324931 is an equidigital number, since it uses as much as digits as its factorization.
101203324931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 29.
The spelling of 101203324931 in words is "one hundred one billion, two hundred three million, three hundred twenty-four thousand, nine hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •