10121009923 has 2 divisors, whose sum is σ = 10121009924. Its totient is φ = 10121009922.

The previous prime is 10121009897. The next prime is 10121010013. The reversal of 10121009923 is 32990012101.

It is a weak prime.

It is an emirp because it is prime and its reverse (32990012101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10121009923 - 2¹⁷ = 10120878851 is a prime.

It is a super-2 number, since 2×10121009923² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10121009891 and 10121009900.

It is not a weakly prime, because it can be changed into another prime (10121009323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060504961 + 5060504962.

It is an arithmetic number, because the mean of its divisors is an integer number (5060504962).

Almost surely, 2^10121009923 is an apocalyptic number.

10121009923 is a deficient number, since it is larger than the sum of its proper divisors (1).

10121009923 is an equidigital number, since it uses as much as digits as its factorization.

10121009923 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 28.

The spelling of 10121009923 in words is "ten billion, one hundred twenty-one million, nine thousand, nine hundred twenty-three".