Base | Representation |
---|---|
bin | 11101011101001101001… |
… | …01010000101010011001 |
3 | 10120202102211110212010002 |
4 | 32232212211100222121 |
5 | 113040301144144433 |
6 | 2052542522502345 |
7 | 133060036621631 |
oct | 16564645205231 |
9 | 3522384425102 |
10 | 1012112099993 |
11 | 360263992995 |
12 | 1441a23649b5 |
13 | 7459871c507 |
14 | 36db4cc56c1 |
15 | 1b4d9c7b9e8 |
hex | eba6950a99 |
1012112099993 has 2 divisors, whose sum is σ = 1012112099994. Its totient is φ = 1012112099992.
The previous prime is 1012112099969. The next prime is 1012112100019. The reversal of 1012112099993 is 3999902112101.
1012112099993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 842555096464 + 169557003529 = 917908^2 + 411773^2 .
It is a cyclic number.
It is not a de Polignac number, because 1012112099993 - 28 = 1012112099737 is a prime.
It is not a weakly prime, because it can be changed into another prime (1012112099393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506056049996 + 506056049997.
It is an arithmetic number, because the mean of its divisors is an integer number (506056049997).
Almost surely, 21012112099993 is an apocalyptic number.
It is an amenable number.
1012112099993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012112099993 is an equidigital number, since it uses as much as digits as its factorization.
1012112099993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78732, while the sum is 47.
The spelling of 1012112099993 in words is "one trillion, twelve billion, one hundred twelve million, ninety-nine thousand, nine hundred ninety-three".
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