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1012113131 is a prime number
BaseRepresentation
bin111100010100111…
…001111011101011
32121112110200012112
4330110321323223
54033100110011
6244233032535
734036551101
oct7424717353
92545420175
101012113131
1147a347637
12242b5574b
131318bb813
14985c1c71
155dcc558b
hex3c539eeb

1012113131 has 2 divisors, whose sum is σ = 1012113132. Its totient is φ = 1012113130.

The previous prime is 1012113121. The next prime is 1012113149. The reversal of 1012113131 is 1313112101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1012113131 is a prime.

It is a super-2 number, since 2×10121131312 = 2048745979885246322, which contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (1012113101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506056565 + 506056566.

It is an arithmetic number, because the mean of its divisors is an integer number (506056566).

Almost surely, 21012113131 is an apocalyptic number.

1012113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012113131 is an equidigital number, since it uses as much as digits as its factorization.

1012113131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

The square root of 1012113131 is about 31813.7255127406. The cubic root of 1012113131 is about 1004.0215160624.

Adding to 1012113131 its reverse (1313112101), we get a palindrome (2325225232).

The spelling of 1012113131 in words is "one billion, twelve million, one hundred thirteen thousand, one hundred thirty-one".