Search a number
-
+
1012123421147 is a prime number
BaseRepresentation
bin11101011101001110100…
…00011100100111011011
310120202110121210000211002
432232213100130213123
5113040312043434042
62052544005255215
7133060235063126
oct16564720344733
93522417700732
101012123421147
1136026a315713
121441a610450b
137459ab84517
1436db65d13bd
151b4dac66132
hexeba741c9db

1012123421147 has 2 divisors, whose sum is σ = 1012123421148. Its totient is φ = 1012123421146.

The previous prime is 1012123421129. The next prime is 1012123421149. The reversal of 1012123421147 is 7411243212101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1012123421147 - 220 = 1012122372571 is a prime.

Together with 1012123421149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1012123421149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506061710573 + 506061710574.

It is an arithmetic number, because the mean of its divisors is an integer number (506061710574).

Almost surely, 21012123421147 is an apocalyptic number.

1012123421147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012123421147 is an equidigital number, since it uses as much as digits as its factorization.

1012123421147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2688, while the sum is 29.

Adding to 1012123421147 its reverse (7411243212101), we get a palindrome (8423366633248).

The spelling of 1012123421147 in words is "one trillion, twelve billion, one hundred twenty-three million, four hundred twenty-one thousand, one hundred forty-seven".