Base | Representation |
---|---|
bin | 111100010101010… |
… | …000000111101101 |
3 | 2121112122021212112 |
4 | 330111100013231 |
5 | 4033111012023 |
6 | 244235013405 |
7 | 34040410052 |
oct | 7425200755 |
9 | 2545567775 |
10 | 1012204013 |
11 | 47a3a9947 |
12 | 242b9a265 |
13 | 131920cb2 |
14 | 98607029 |
15 | 5dce2478 |
hex | 3c5501ed |
1012204013 has 2 divisors, whose sum is σ = 1012204014. Its totient is φ = 1012204012.
The previous prime is 1012203991. The next prime is 1012204019. The reversal of 1012204013 is 3104022101.
1012204013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 542051524 + 470152489 = 23282^2 + 21683^2 .
It is a cyclic number.
It is not a de Polignac number, because 1012204013 - 226 = 945095149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012204019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506102006 + 506102007.
It is an arithmetic number, because the mean of its divisors is an integer number (506102007).
Almost surely, 21012204013 is an apocalyptic number.
It is an amenable number.
1012204013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012204013 is an equidigital number, since it uses as much as digits as its factorization.
1012204013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 14.
The square root of 1012204013 is about 31815.1538264394. The cubic root of 1012204013 is about 1004.0515669693.
Adding to 1012204013 its reverse (3104022101), we get a palindrome (4116226114).
The spelling of 1012204013 in words is "one billion, twelve million, two hundred four thousand, thirteen".
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