Base | Representation |
---|---|
bin | 10111000000111101011001… |
… | …110100100010110011111011 |
3 | 111021101122002121111200222122 |
4 | 113000331121310202303323 |
5 | 101231401102302224011 |
6 | 555140141440111455 |
7 | 30214655525166134 |
oct | 2700753164426373 |
9 | 437348077450878 |
10 | 101221001211131 |
11 | 2a2856493a2aaa |
12 | b42938460558b |
13 | 446313a67aaa9 |
14 | 1add1a05a6c8b |
15 | ba7ecd0963db |
hex | 5c0f59d22cfb |
101221001211131 has 2 divisors, whose sum is σ = 101221001211132. Its totient is φ = 101221001211130.
The previous prime is 101221001211101. The next prime is 101221001211139. The reversal of 101221001211131 is 131112100122101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101221001211131 is a prime.
It is a super-2 number, since 2×1012210012111312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101221001211139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50610500605565 + 50610500605566.
It is an arithmetic number, because the mean of its divisors is an integer number (50610500605566).
Almost surely, 2101221001211131 is an apocalyptic number.
101221001211131 is a deficient number, since it is larger than the sum of its proper divisors (1).
101221001211131 is an equidigital number, since it uses as much as digits as its factorization.
101221001211131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 101221001211131 its reverse (131112100122101), we get a palindrome (232333101333232).
The spelling of 101221001211131 in words is "one hundred one trillion, two hundred twenty-one billion, one million, two hundred eleven thousand, one hundred thirty-one".
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