10122110113 has 2 divisors, whose sum is σ = 10122110114. Its totient is φ = 10122110112.

The previous prime is 10122110107. The next prime is 10122110153. The reversal of 10122110113 is 31101122101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5668282944 + 4453827169 = 75288^2 + 66737^2 .

It is a cyclic number.

It is not a de Polignac number, because 10122110113 - 2⁵ = 10122110081 is a prime.

It is a super-2 number, since 2×10122110113² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10122110093 and 10122110102.

It is not a weakly prime, because it can be changed into another prime (10122110153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061055056 + 5061055057.

It is an arithmetic number, because the mean of its divisors is an integer number (5061055057).

Almost surely, 2^10122110113 is an apocalyptic number.

It is an amenable number.

10122110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10122110113 is an equidigital number, since it uses as much as digits as its factorization.

10122110113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10122110113 its reverse (31101122101), we get a palindrome (41223232214).

The spelling of 10122110113 in words is "ten billion, one hundred twenty-two million, one hundred ten thousand, one hundred thirteen".