Search a number
-
+
101221221151 is a prime number
BaseRepresentation
bin101111001000101000…
…0010100001100011111
3100200021021120210201201
41132101100110030133
53124300113034101
6114300030020331
710212233120011
oct1362120241437
9320237523651
10101221221151
1139a22816686
121774a9476a7
1397118240cb
144c833161b1
152976567e01
hex179141431f

101221221151 has 2 divisors, whose sum is σ = 101221221152. Its totient is φ = 101221221150.

The previous prime is 101221221113. The next prime is 101221221307. The reversal of 101221221151 is 151122122101.

It is a weak prime.

It is an emirp because it is prime and its reverse (151122122101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101221221151 - 217 = 101221090079 is a prime.

It is a super-2 number, since 2×1012212211512 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101221231151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50610610575 + 50610610576.

It is an arithmetic number, because the mean of its divisors is an integer number (50610610576).

Almost surely, 2101221221151 is an apocalyptic number.

101221221151 is a deficient number, since it is larger than the sum of its proper divisors (1).

101221221151 is an equidigital number, since it uses as much as digits as its factorization.

101221221151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80, while the sum is 19.

Adding to 101221221151 its reverse (151122122101), we get a palindrome (252343343252).

The spelling of 101221221151 in words is "one hundred one billion, two hundred twenty-one million, two hundred twenty-one thousand, one hundred fifty-one".