Base | Representation |
---|---|
bin | 11101011101011010001… |
… | …01000110011011101001 |
3 | 10120202201102121010201111 |
4 | 32232231011012123221 |
5 | 113041012101004433 |
6 | 2053001415150321 |
7 | 133062532321222 |
oct | 16565505063351 |
9 | 3522642533644 |
10 | 1012221109993 |
11 | 36030a4787a5 |
12 | 1442129753a1 |
13 | 745b5199082 |
14 | 36dc5580249 |
15 | 1b4e4610dcd |
hex | ebad1466e9 |
1012221109993 has 2 divisors, whose sum is σ = 1012221109994. Its totient is φ = 1012221109992.
The previous prime is 1012221109973. The next prime is 1012221110053. The reversal of 1012221109993 is 3999011222101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 884562822144 + 127658287849 = 940512^2 + 357293^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1012221109993 is a prime.
It is a super-2 number, since 2×10122211099932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1012221109973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506110554996 + 506110554997.
It is an arithmetic number, because the mean of its divisors is an integer number (506110554997).
Almost surely, 21012221109993 is an apocalyptic number.
It is an amenable number.
1012221109993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012221109993 is an equidigital number, since it uses as much as digits as its factorization.
1012221109993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 40.
The spelling of 1012221109993 in words is "one trillion, twelve billion, two hundred twenty-one million, one hundred nine thousand, nine hundred ninety-three".
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