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1012221109993 is a prime number
BaseRepresentation
bin11101011101011010001…
…01000110011011101001
310120202201102121010201111
432232231011012123221
5113041012101004433
62053001415150321
7133062532321222
oct16565505063351
93522642533644
101012221109993
1136030a4787a5
121442129753a1
13745b5199082
1436dc5580249
151b4e4610dcd
hexebad1466e9

1012221109993 has 2 divisors, whose sum is σ = 1012221109994. Its totient is φ = 1012221109992.

The previous prime is 1012221109973. The next prime is 1012221110053. The reversal of 1012221109993 is 3999011222101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 884562822144 + 127658287849 = 940512^2 + 357293^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1012221109993 is a prime.

It is a super-2 number, since 2×10122211099932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1012221109973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506110554996 + 506110554997.

It is an arithmetic number, because the mean of its divisors is an integer number (506110554997).

Almost surely, 21012221109993 is an apocalyptic number.

It is an amenable number.

1012221109993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012221109993 is an equidigital number, since it uses as much as digits as its factorization.

1012221109993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 40.

The spelling of 1012221109993 in words is "one trillion, twelve billion, two hundred twenty-one million, one hundred nine thousand, nine hundred ninety-three".