Base | Representation |
---|---|
bin | 11101011101011010001… |
… | …01000110011100100101 |
3 | 10120202201102121010210201 |
4 | 32232231011012130211 |
5 | 113041012101010203 |
6 | 2053001415150501 |
7 | 133062532321336 |
oct | 16565505063445 |
9 | 3522642533721 |
10 | 1012221110053 |
11 | 36030a47884a |
12 | 144212975431 |
13 | 745b51990ca |
14 | 36dc558028d |
15 | 1b4e4610e1d |
hex | ebad146725 |
1012221110053 has 2 divisors, whose sum is σ = 1012221110054. Its totient is φ = 1012221110052.
The previous prime is 1012221109993. The next prime is 1012221110077. The reversal of 1012221110053 is 3500111222101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1010392863489 + 1828246564 = 1005183^2 + 42758^2 .
It is a cyclic number.
It is not a de Polignac number, because 1012221110053 - 213 = 1012221101861 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1012221110053.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012221110353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506110555026 + 506110555027.
It is an arithmetic number, because the mean of its divisors is an integer number (506110555027).
Almost surely, 21012221110053 is an apocalyptic number.
It is an amenable number.
1012221110053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012221110053 is an equidigital number, since it uses as much as digits as its factorization.
1012221110053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 1012221110053 its reverse (3500111222101), we get a palindrome (4512332332154).
The spelling of 1012221110053 in words is "one trillion, twelve billion, two hundred twenty-one million, one hundred ten thousand, fifty-three".
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