101222113 has 2 divisors, whose sum is σ = 101222114. Its totient is φ = 101222112.

The previous prime is 101222083. The next prime is 101222137. The reversal of 101222113 is 311222101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89340304 + 11881809 = 9452^2 + 3447^2 .

It is an emirp because it is prime and its reverse (311222101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101222113 - 2⁵ = 101222081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101222093 and 101222102.

It is not a weakly prime, because it can be changed into another prime (101222213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50611056 + 50611057.

It is an arithmetic number, because the mean of its divisors is an integer number (50611057).

Almost surely, 2^101222113 is an apocalyptic number.

It is an amenable number.

101222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101222113 is an equidigital number, since it uses as much as digits as its factorization.

101222113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 101222113 is about 10060.9200871491. The cubic root of 101222113 is about 466.0420811526.

Adding to 101222113 its reverse (311222101), we get a palindrome (412444214).

The spelling of 101222113 in words is "one hundred one million, two hundred twenty-two thousand, one hundred thirteen".