Base | Representation |
---|---|
bin | 11101011101011010001… |
… | …01100010000001110111 |
3 | 10120202201102210212210002 |
4 | 32232231011202001313 |
5 | 113041012113114111 |
6 | 2053001421421515 |
7 | 133062533301614 |
oct | 16565505420167 |
9 | 3522642725702 |
10 | 1012221223031 |
11 | 36030a545717 |
12 | 144212a0a89b |
13 | 745b5208665 |
14 | 36dc55ad50b |
15 | 1b4e463463b |
hex | ebad162077 |
1012221223031 has 2 divisors, whose sum is σ = 1012221223032. Its totient is φ = 1012221223030.
The previous prime is 1012221223021. The next prime is 1012221223037. The reversal of 1012221223031 is 1303221222101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1012221223031 - 210 = 1012221222007 is a prime.
It is a super-3 number, since 3×10122212230313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1012221222994 and 1012221223012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012221223037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506110611515 + 506110611516.
It is an arithmetic number, because the mean of its divisors is an integer number (506110611516).
Almost surely, 21012221223031 is an apocalyptic number.
1012221223031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012221223031 is an equidigital number, since it uses as much as digits as its factorization.
1012221223031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 1012221223031 its reverse (1303221222101), we get a palindrome (2315442445132).
The spelling of 1012221223031 in words is "one trillion, twelve billion, two hundred twenty-one million, two hundred twenty-three thousand, thirty-one".
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