Base | Representation |
---|---|
bin | 11101011101011010010… |
… | …00100010101011110011 |
3 | 10120202201111021222020121 |
4 | 32232231020202223303 |
5 | 113041012313342042 |
6 | 2053001450351111 |
7 | 133062543066343 |
oct | 16565510425363 |
9 | 3522644258217 |
10 | 1012222012147 |
11 | 36030aa34585 |
12 | 14421312b497 |
13 | 745b54238a8 |
14 | 36dc5736d23 |
15 | 1b4e473d367 |
hex | ebad222af3 |
1012222012147 has 2 divisors, whose sum is σ = 1012222012148. Its totient is φ = 1012222012146.
The previous prime is 1012222012141. The next prime is 1012222012157. The reversal of 1012222012147 is 7412102222101.
It is a weak prime.
It is an emirp because it is prime and its reverse (7412102222101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1012222012147 - 231 = 1010074528499 is a prime.
It is not a weakly prime, because it can be changed into another prime (1012222012141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506111006073 + 506111006074.
It is an arithmetic number, because the mean of its divisors is an integer number (506111006074).
Almost surely, 21012222012147 is an apocalyptic number.
1012222012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012222012147 is an equidigital number, since it uses as much as digits as its factorization.
1012222012147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 1012222012147 its reverse (7412102222101), we get a palindrome (8424324234248).
The spelling of 1012222012147 in words is "one trillion, twelve billion, two hundred twenty-two million, twelve thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •