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101222231120093 is a prime number
BaseRepresentation
bin10111000000111110100011…
…001000010001100011011101
3111021101202021022210112220102
4113000332203020101203131
5101231411112131320333
6555140503453230445
730215031151223426
oct2700764310214335
9437352238715812
10101222231120093
112a28611a677896
12b429668492425
1344632a5414985
141add279a8064d
15ba805103dae8
hex5c0fa32118dd

101222231120093 has 2 divisors, whose sum is σ = 101222231120094. Its totient is φ = 101222231120092.

The previous prime is 101222231120057. The next prime is 101222231120159. The reversal of 101222231120093 is 390021132222101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83067584396164 + 18154646723929 = 9114142^2 + 4260827^2 .

It is a cyclic number.

It is not a de Polignac number, because 101222231120093 - 212 = 101222231115997 is a prime.

It is a super-3 number, since 3×1012222311200933 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101222231120393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50611115560046 + 50611115560047.

It is an arithmetic number, because the mean of its divisors is an integer number (50611115560047).

Almost surely, 2101222231120093 is an apocalyptic number.

It is an amenable number.

101222231120093 is a deficient number, since it is larger than the sum of its proper divisors (1).

101222231120093 is an equidigital number, since it uses as much as digits as its factorization.

101222231120093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 29.

Adding to 101222231120093 its reverse (390021132222101), we get a palindrome (491243363342194).

The spelling of 101222231120093 in words is "one hundred one trillion, two hundred twenty-two billion, two hundred thirty-one million, one hundred twenty thousand, ninety-three".