Base | Representation |
---|---|
bin | 1001001101001100111111… |
… | …1011011110001111101111 |
3 | 1022211200202122112222021222 |
4 | 2103103033323132033233 |
5 | 2311321214421022341 |
6 | 33310103015213555 |
7 | 2063215200311003 |
oct | 223231773361757 |
9 | 38750678488258 |
10 | 10122431423471 |
11 | 3252998713624 |
12 | 11759659772bb |
13 | 585705cb13b3 |
14 | 26dcdd354703 |
15 | 1284935ca44b |
hex | 934cfede3ef |
10122431423471 has 2 divisors, whose sum is σ = 10122431423472. Its totient is φ = 10122431423470.
The previous prime is 10122431423459. The next prime is 10122431423479. The reversal of 10122431423471 is 17432413422101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10122431423471 - 226 = 10122364314607 is a prime.
It is a super-3 number, since 3×101224314234713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10122431423479) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061215711735 + 5061215711736.
It is an arithmetic number, because the mean of its divisors is an integer number (5061215711736).
Almost surely, 210122431423471 is an apocalyptic number.
10122431423471 is a deficient number, since it is larger than the sum of its proper divisors (1).
10122431423471 is an equidigital number, since it uses as much as digits as its factorization.
10122431423471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 10122431423471 its reverse (17432413422101), we get a palindrome (27554844845572).
The spelling of 10122431423471 in words is "ten trillion, one hundred twenty-two billion, four hundred thirty-one million, four hundred twenty-three thousand, four hundred seventy-one".
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