Base | Representation |
---|---|
bin | 101111001000111001… |
… | …0001111001000010101 |
3 | 100200021220022120110121 |
4 | 1132101302033020111 |
5 | 3124304402111201 |
6 | 114300544351541 |
7 | 10212401523442 |
oct | 1362162171025 |
9 | 320256276417 |
10 | 101230113301 |
11 | 39a2783a469 |
12 | 177519155b1 |
13 | 9713618635 |
14 | 4c8458c9c9 |
15 | 29772229a1 |
hex | 1791c8f215 |
101230113301 has 2 divisors, whose sum is σ = 101230113302. Its totient is φ = 101230113300.
The previous prime is 101230113293. The next prime is 101230113311. The reversal of 101230113301 is 103311032101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 65961648900 + 35268464401 = 256830^2 + 187799^2 .
It is a cyclic number.
It is not a de Polignac number, because 101230113301 - 23 = 101230113293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101230113311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50615056650 + 50615056651.
It is an arithmetic number, because the mean of its divisors is an integer number (50615056651).
Almost surely, 2101230113301 is an apocalyptic number.
It is an amenable number.
101230113301 is a deficient number, since it is larger than the sum of its proper divisors (1).
101230113301 is an equidigital number, since it uses as much as digits as its factorization.
101230113301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 101230113301 its reverse (103311032101), we get a palindrome (204541145402).
The spelling of 101230113301 in words is "one hundred one billion, two hundred thirty million, one hundred thirteen thousand, three hundred one".
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