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10123341431153 is a prime number
BaseRepresentation
bin1001001101010000011000…
…1010111000000101110001
31022211210010001220011011012
42103110012022320011301
52311330100401244103
633310333204000305
72063246560250426
oct223240612700561
938753101804135
1010123341431153
113253315360895
121175b7a690095
1358581c69cc92
1426dd88157d4d
151284e84322d8
hex935062b8171

10123341431153 has 2 divisors, whose sum is σ = 10123341431154. Its totient is φ = 10123341431152.

The previous prime is 10123341431129. The next prime is 10123341431201. The reversal of 10123341431153 is 35113414332101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9048743820769 + 1074597610384 = 3008113^2 + 1036628^2 .

It is a cyclic number.

It is not a de Polignac number, because 10123341431153 - 226 = 10123274322289 is a prime.

It is not a weakly prime, because it can be changed into another prime (10123341431653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061670715576 + 5061670715577.

It is an arithmetic number, because the mean of its divisors is an integer number (5061670715577).

Almost surely, 210123341431153 is an apocalyptic number.

It is an amenable number.

10123341431153 is a deficient number, since it is larger than the sum of its proper divisors (1).

10123341431153 is an equidigital number, since it uses as much as digits as its factorization.

10123341431153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 10123341431153 its reverse (35113414332101), we get a palindrome (45236755763254).

The spelling of 10123341431153 in words is "ten trillion, one hundred twenty-three billion, three hundred forty-one million, four hundred thirty-one thousand, one hundred fifty-three".