Base | Representation |
---|---|
bin | 101111001000111111… |
… | …1010011110001101111 |
3 | 100200022010202200022001 |
4 | 1132101333103301233 |
5 | 3124311241241312 |
6 | 114301150033131 |
7 | 10212442615432 |
oct | 1362177236157 |
9 | 320263680261 |
10 | 101233540207 |
11 | 39a29770118 |
12 | 17752aa87a7 |
13 | 97142483a7 |
14 | 4c84c01819 |
15 | 297769d057 |
hex | 1791fd3c6f |
101233540207 has 2 divisors, whose sum is σ = 101233540208. Its totient is φ = 101233540206.
The previous prime is 101233540117. The next prime is 101233540249. The reversal of 101233540207 is 702045332101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101233540207 - 215 = 101233507439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101233540607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50616770103 + 50616770104.
It is an arithmetic number, because the mean of its divisors is an integer number (50616770104).
Almost surely, 2101233540207 is an apocalyptic number.
101233540207 is a deficient number, since it is larger than the sum of its proper divisors (1).
101233540207 is an equidigital number, since it uses as much as digits as its factorization.
101233540207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 28.
Adding to 101233540207 its reverse (702045332101), we get a palindrome (803278872308).
The spelling of 101233540207 in words is "one hundred one billion, two hundred thirty-three million, five hundred forty thousand, two hundred seven".
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