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10125050473 is a prime number
BaseRepresentation
bin10010110111000000…
…00000001001101001
3222010122001212010101
421123200000021221
5131214003103343
64352410545401
7505623336406
oct113340001151
928118055111
1010125050473
11432636630a
121b66a38261
13c54892135
146c09d52ad
153e3d5ee4d
hex25b800269

10125050473 has 2 divisors, whose sum is σ = 10125050474. Its totient is φ = 10125050472.

The previous prime is 10125050437. The next prime is 10125050497. The reversal of 10125050473 is 37405052101.

It is a happy number.

10125050473 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (10125050437) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9159829849 + 965220624 = 95707^2 + 31068^2 .

It is an emirp because it is prime and its reverse (37405052101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10125050473 is a prime.

It is not a weakly prime, because it can be changed into another prime (10125050423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5062525236 + 5062525237.

It is an arithmetic number, because the mean of its divisors is an integer number (5062525237).

Almost surely, 210125050473 is an apocalyptic number.

It is an amenable number.

10125050473 is a deficient number, since it is larger than the sum of its proper divisors (1).

10125050473 is an equidigital number, since it uses as much as digits as its factorization.

10125050473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4200, while the sum is 28.

The spelling of 10125050473 in words is "ten billion, one hundred twenty-five million, fifty thousand, four hundred seventy-three".