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10129936471 is a prime number
BaseRepresentation
bin10010110111100101…
…01001000001010111
3222010222021002110021
421123302221001113
5131221230431341
64353103410011
7506013016324
oct113362510127
928128232407
1010129936471
1143290a3226
121b685b3907
13c558b3065
146c1507b4b
153e44c79d1
hex25bca9057

10129936471 has 2 divisors, whose sum is σ = 10129936472. Its totient is φ = 10129936470.

The previous prime is 10129936463. The next prime is 10129936477. The reversal of 10129936471 is 17463992101.

10129936471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10129936471 - 23 = 10129936463 is a prime.

It is a super-3 number, since 3×101299364713 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10129936477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5064968235 + 5064968236.

It is an arithmetic number, because the mean of its divisors is an integer number (5064968236).

Almost surely, 210129936471 is an apocalyptic number.

10129936471 is a deficient number, since it is larger than the sum of its proper divisors (1).

10129936471 is an equidigital number, since it uses as much as digits as its factorization.

10129936471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81648, while the sum is 43.

The spelling of 10129936471 in words is "ten billion, one hundred twenty-nine million, nine hundred thirty-six thousand, four hundred seventy-one".