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10130011313102 = 25065005656551
BaseRepresentation
bin1001001101101001001110…
…1110011101001111001110
31022212102022220110021002222
42103122103232131033032
52311432230344004402
633313355110415342
72063604060310412
oct223322356351716
938772286407088
1010130011313102
11325612832a91a
121177320361552
135863434914a5
1427041bd00d42
15128788c8d7a2
hex93693b9d3ce

10130011313102 has 4 divisors (see below), whose sum is σ = 15195016969656. Its totient is φ = 5065005656550.

The previous prime is 10130011313077. The next prime is 10130011313111. The reversal of 10130011313102 is 20131311003101.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2532502828274 + ... + 2532502828277.

It is an arithmetic number, because the mean of its divisors is an integer number (3798754242414).

Almost surely, 210130011313102 is an apocalyptic number.

10130011313102 is a deficient number, since it is larger than the sum of its proper divisors (5065005656554).

10130011313102 is an equidigital number, since it uses as much as digits as its factorization.

10130011313102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5065005656553.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10130011313102 its reverse (20131311003101), we get a palindrome (30261322316203).

The spelling of 10130011313102 in words is "ten trillion, one hundred thirty billion, eleven million, three hundred thirteen thousand, one hundred two".

Divisors: 1 2 5065005656551 10130011313102