Base | Representation |
---|---|
bin | 1001001101101001001110… |
… | …1110011101001111010111 |
3 | 1022212102022220110021010022 |
4 | 2103122103232131033113 |
5 | 2311432230344004421 |
6 | 33313355110415355 |
7 | 2063604060310424 |
oct | 223322356351727 |
9 | 38772286407108 |
10 | 10130011313111 |
11 | 325612832a928 |
12 | 117732036155b |
13 | 5863434914b1 |
14 | 27041bd00d4b |
15 | 128788c8d7ab |
hex | 93693b9d3d7 |
10130011313111 has 2 divisors, whose sum is σ = 10130011313112. Its totient is φ = 10130011313110.
The previous prime is 10130011313077. The next prime is 10130011313117. The reversal of 10130011313111 is 11131311003101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10130011313111 - 222 = 10130007118807 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10130011313111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10130011313117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065005656555 + 5065005656556.
It is an arithmetic number, because the mean of its divisors is an integer number (5065005656556).
Almost surely, 210130011313111 is an apocalyptic number.
10130011313111 is a deficient number, since it is larger than the sum of its proper divisors (1).
10130011313111 is an equidigital number, since it uses as much as digits as its factorization.
10130011313111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 17.
Adding to 10130011313111 its reverse (11131311003101), we get a palindrome (21261322316212).
The spelling of 10130011313111 in words is "ten trillion, one hundred thirty billion, eleven million, three hundred thirteen thousand, one hundred eleven".
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