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101300212103 is a prime number
BaseRepresentation
bin101111001010111110…
…1101001000110000111
3100200110210012221221112
41132111331221012013
53124430323241403
6114311531035235
710214212411226
oct1362575510607
9320423187845
10101300212103
1139a63368762
121777129bb1b
139724cc010c
144c8d9d8cbd
15297d46c9d8
hex1795f69187

101300212103 has 2 divisors, whose sum is σ = 101300212104. Its totient is φ = 101300212102.

The previous prime is 101300212043. The next prime is 101300212157. The reversal of 101300212103 is 301212003101.

It is a strong prime.

It is an emirp because it is prime and its reverse (301212003101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101300212103 - 220 = 101299163527 is a prime.

It is a super-2 number, since 2×1013002121032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101300212163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50650106051 + 50650106052.

It is an arithmetic number, because the mean of its divisors is an integer number (50650106052).

Almost surely, 2101300212103 is an apocalyptic number.

101300212103 is a deficient number, since it is larger than the sum of its proper divisors (1).

101300212103 is an equidigital number, since it uses as much as digits as its factorization.

101300212103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 101300212103 its reverse (301212003101), we get a palindrome (402512215204).

The spelling of 101300212103 in words is "one hundred one billion, three hundred million, two hundred twelve thousand, one hundred three".