Search a number
-
+
10130112131 is a prime number
BaseRepresentation
bin10010110111100110…
…10011111010000011
3222010222121000102012
421123303103322003
5131221302042011
64353111243135
7506014350416
oct113363237203
928128530365
1010130112131
1143292031a7
121b686794ab
13c55944cb9
146c1551b7d
153e450ea8b
hex25bcd3e83

10130112131 has 2 divisors, whose sum is σ = 10130112132. Its totient is φ = 10130112130.

The previous prime is 10130112127. The next prime is 10130112137. The reversal of 10130112131 is 13121103101.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (13121103101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10130112131 - 22 = 10130112127 is a prime.

It is a super-2 number, since 2×101301121312 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10130112137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065056065 + 5065056066.

It is an arithmetic number, because the mean of its divisors is an integer number (5065056066).

Almost surely, 210130112131 is an apocalyptic number.

10130112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10130112131 is an equidigital number, since it uses as much as digits as its factorization.

10130112131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 10130112131 its reverse (13121103101), we get a palindrome (23251215232).

The spelling of 10130112131 in words is "ten billion, one hundred thirty million, one hundred twelve thousand, one hundred thirty-one".