Base | Representation |
---|---|
bin | 10010110111101000… |
… | …11111000111110101 |
3 | 222011000011200000122 |
4 | 21123310133013311 |
5 | 131221341421323 |
6 | 4353122021325 |
7 | 506020102544 |
oct | 113364370765 |
9 | 28130150018 |
10 | 10130420213 |
11 | 43293a3711 |
12 | 1b687a7845 |
13 | c55a222b4 |
14 | 6c15d215b |
15 | 3e4570ec8 |
hex | 25bd1f1f5 |
10130420213 has 2 divisors, whose sum is σ = 10130420214. Its totient is φ = 10130420212.
The previous prime is 10130420203. The next prime is 10130420221. The reversal of 10130420213 is 31202403101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5944718404 + 4185701809 = 77102^2 + 64697^2 .
It is a cyclic number.
It is not a de Polignac number, because 10130420213 - 222 = 10126225909 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 10130420191 and 10130420200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10130420203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065210106 + 5065210107.
It is an arithmetic number, because the mean of its divisors is an integer number (5065210107).
Almost surely, 210130420213 is an apocalyptic number.
It is an amenable number.
10130420213 is a deficient number, since it is larger than the sum of its proper divisors (1).
10130420213 is an equidigital number, since it uses as much as digits as its factorization.
10130420213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 10130420213 its reverse (31202403101), we get a palindrome (41332823314).
The spelling of 10130420213 in words is "ten billion, one hundred thirty million, four hundred twenty thousand, two hundred thirteen".
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