101310012000031 has 2 divisors, whose sum is σ = 101310012000032. Its totient is φ = 101310012000030.

The previous prime is 101310012000019. The next prime is 101310012000059. The reversal of 101310012000031 is 130000210013101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101310012000031 - 2¹¹ = 101310011997983 is a prime.

It is a super-3 number, since 3×101310012000031³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 101310011999975 and 101310012000020.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101310012000061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50655006000015 + 50655006000016.

It is an arithmetic number, because the mean of its divisors is an integer number (50655006000016).

Almost surely, 2^{101310012000031} is an apocalyptic number.

101310012000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

101310012000031 is an equidigital number, since it uses as much as digits as its factorization.

101310012000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 101310012000031 its reverse (130000210013101), we get a palindrome (231310222013132).

The spelling of 101310012000031 in words is "one hundred one trillion, three hundred ten billion, twelve million, thirty-one", and thus it is an aban number.