Base | Representation |
---|---|
bin | 10111000010010000100000… |
… | …010101100011111110010101 |
3 | 111021201011102012021210001212 |
4 | 113002100200111203332111 |
5 | 101234331323130220313 |
6 | 555245135550231205 |
7 | 30224264653556462 |
oct | 2702204025437625 |
9 | 437634365253055 |
10 | 101310231101333 |
11 | 2a30a478339211 |
12 | b4427274b5505 |
13 | 446b68aa841a7 |
14 | 1b036270ba669 |
15 | baa4a1a023a8 |
hex | 5c2420563f95 |
101310231101333 has 2 divisors, whose sum is σ = 101310231101334. Its totient is φ = 101310231101332.
The previous prime is 101310231101273. The next prime is 101310231101347. The reversal of 101310231101333 is 333101132013101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 56711849148529 + 44598381952804 = 7530727^2 + 6678202^2 .
It is an emirp because it is prime and its reverse (333101132013101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101310231101333 - 28 = 101310231101077 is a prime.
It is a super-2 number, since 2×1013102311013332 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 101310231101299 and 101310231101308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101310231106333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50655115550666 + 50655115550667.
It is an arithmetic number, because the mean of its divisors is an integer number (50655115550667).
Almost surely, 2101310231101333 is an apocalyptic number.
It is an amenable number.
101310231101333 is a deficient number, since it is larger than the sum of its proper divisors (1).
101310231101333 is an equidigital number, since it uses as much as digits as its factorization.
101310231101333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 101310231101333 its reverse (333101132013101), we get a palindrome (434411363114434).
The spelling of 101310231101333 in words is "one hundred one trillion, three hundred ten billion, two hundred thirty-one million, one hundred one thousand, three hundred thirty-three".
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