10131113114341 has 4 divisors (see below), whose sum is σ = 10302826896000. Its totient is φ = 9959399332684.

The previous prime is 10131113114323. The next prime is 10131113114387. The reversal of 10131113114341 is 14341131113101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10131113114341 - 2²¹ = 10131111017189 is a prime.

It is a super-2 number, since 2×10131113114341² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10131113114041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85856890741 + ... + 85856890858.

It is an arithmetic number, because the mean of its divisors is an integer number (2575706724000).

Almost surely, 2^{10131113114341} is an apocalyptic number.

It is an amenable number.

10131113114341 is a deficient number, since it is larger than the sum of its proper divisors (171713781659).

10131113114341 is an equidigital number, since it uses as much as digits as its factorization.

10131113114341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171713781658.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 10131113114341 its reverse (14341131113101), we get a palindrome (24472244227442).

The spelling of 10131113114341 in words is "ten trillion, one hundred thirty-one billion, one hundred thirteen million, one hundred fourteen thousand, three hundred forty-one".