Base | Representation |
---|---|
bin | 11101011111000100100… |
… | …11101000110001101101 |
3 | 10120212000122221101201212 |
4 | 32233202103220301231 |
5 | 113044324203110013 |
6 | 2053230155244205 |
7 | 133123624606013 |
oct | 16574223506155 |
9 | 3525018841655 |
10 | 1013114113133 |
11 | 360728561221 |
12 | 144421a49665 |
13 | 746c81b2ab5 |
14 | 3706bdd88b3 |
15 | 1b547c096a8 |
hex | ebe24e8c6d |
1013114113133 has 2 divisors, whose sum is σ = 1013114113134. Its totient is φ = 1013114113132.
The previous prime is 1013114113073. The next prime is 1013114113159. The reversal of 1013114113133 is 3313114113101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 998694426409 + 14419686724 = 999347^2 + 120082^2 .
It is a cyclic number.
It is not a de Polignac number, because 1013114113133 - 214 = 1013114096749 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1013114113099 and 1013114113108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1013114113933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506557056566 + 506557056567.
It is an arithmetic number, because the mean of its divisors is an integer number (506557056567).
Almost surely, 21013114113133 is an apocalyptic number.
It is an amenable number.
1013114113133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013114113133 is an equidigital number, since it uses as much as digits as its factorization.
1013114113133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 1013114113133 its reverse (3313114113101), we get a palindrome (4326228226234).
The spelling of 1013114113133 in words is "one trillion, thirteen billion, one hundred fourteen million, one hundred thirteen thousand, one hundred thirty-three".
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