Base | Representation |
---|---|
bin | 11101011111000111101… |
… | …11001010001010011101 |
3 | 10120212002111000212010102 |
4 | 32233203313022022131 |
5 | 113044402342432031 |
6 | 2053232530350445 |
7 | 133124362425164 |
oct | 16574367121235 |
9 | 3525074025112 |
10 | 1013140202141 |
11 | 360741260291 |
12 | 14442a72b425 |
13 | 74700718892 |
14 | 3707166a3db |
15 | 1b54a15e7cb |
hex | ebe3dca29d |
1013140202141 has 2 divisors, whose sum is σ = 1013140202142. Its totient is φ = 1013140202140.
The previous prime is 1013140202119. The next prime is 1013140202171. The reversal of 1013140202141 is 1412020413101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 697301822116 + 315838380025 = 835046^2 + 561995^2 .
It is a cyclic number.
It is not a de Polignac number, because 1013140202141 - 26 = 1013140202077 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1013140202171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506570101070 + 506570101071.
It is an arithmetic number, because the mean of its divisors is an integer number (506570101071).
Almost surely, 21013140202141 is an apocalyptic number.
It is an amenable number.
1013140202141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013140202141 is an equidigital number, since it uses as much as digits as its factorization.
1013140202141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1013140202141 its reverse (1412020413101), we get a palindrome (2425160615242).
The spelling of 1013140202141 in words is "one trillion, thirteen billion, one hundred forty million, two hundred two thousand, one hundred forty-one".
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