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1013141434171 is a prime number
BaseRepresentation
bin11101011111000111110…
…11110110111100111011
310120212002120100110011011
432233203323312330323
5113044403201343141
62053233013014351
7133124406046126
oct16574373667473
93525076313134
101013141434171
11360741a21999
1214442b0243b7
1374700a5a5a9
14370718ab3bd
151b54a304881
hexebe3ef6f3b

1013141434171 has 2 divisors, whose sum is σ = 1013141434172. Its totient is φ = 1013141434170.

The previous prime is 1013141434153. The next prime is 1013141434241. The reversal of 1013141434171 is 1714341413101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1013141434171 - 25 = 1013141434139 is a prime.

It is a super-4 number, since 4×10131414341714 (a number of 49 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (1013141434111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506570717085 + 506570717086.

It is an arithmetic number, because the mean of its divisors is an integer number (506570717086).

Almost surely, 21013141434171 is an apocalyptic number.

1013141434171 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013141434171 is an equidigital number, since it uses as much as digits as its factorization.

1013141434171 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 31.

Adding to 1013141434171 its reverse (1714341413101), we get a palindrome (2727482847272).

The spelling of 1013141434171 in words is "one trillion, thirteen billion, one hundred forty-one million, four hundred thirty-four thousand, one hundred seventy-one".