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1013141434241 is a prime number
BaseRepresentation
bin11101011111000111110…
…11110110111110000001
310120212002120100110020202
432233203323312332001
5113044403201343431
62053233013014545
7133124406046256
oct16574373667601
93525076313222
101013141434241
11360741a21a52
1214442b024455
1374700a5a631
14370718ab42d
151b54a3048cb
hexebe3ef6f81

1013141434241 has 2 divisors, whose sum is σ = 1013141434242. Its totient is φ = 1013141434240.

The previous prime is 1013141434171. The next prime is 1013141434247. The reversal of 1013141434241 is 1424341413101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1009432137025 + 3709297216 = 1004705^2 + 60904^2 .

It is an emirp because it is prime and its reverse (1424341413101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1013141434241 - 222 = 1013137239937 is a prime.

It is a super-4 number, since 4×10131414342414 (a number of 49 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (1013141434247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506570717120 + 506570717121.

It is an arithmetic number, because the mean of its divisors is an integer number (506570717121).

Almost surely, 21013141434241 is an apocalyptic number.

It is an amenable number.

1013141434241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013141434241 is an equidigital number, since it uses as much as digits as its factorization.

1013141434241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 1013141434241 its reverse (1424341413101), we get a palindrome (2437482847342).

The spelling of 1013141434241 in words is "one trillion, thirteen billion, one hundred forty-one million, four hundred thirty-four thousand, two hundred forty-one".