1013143314481 has 2 divisors, whose sum is σ = 1013143314482. Its totient is φ = 1013143314480.

The previous prime is 1013143314409. The next prime is 1013143314539. The reversal of 1013143314481 is 1844133413101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 679567760881 + 333575553600 = 824359^2 + 577560^2 .

It is a cyclic number.

It is not a de Polignac number, because 1013143314481 - 2²¹ = 1013141217329 is a prime.

It is a super-2 number, since 2×1013143314481² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1013143914481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506571657240 + 506571657241.

It is an arithmetic number, because the mean of its divisors is an integer number (506571657241).

Almost surely, 2^{1013143314481} is an apocalyptic number.

It is an amenable number.

1013143314481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013143314481 is an equidigital number, since it uses as much as digits as its factorization.

1013143314481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 34.

Adding to 1013143314481 its reverse (1844133413101), we get a palindrome (2857276727582).

The spelling of 1013143314481 in words is "one trillion, thirteen billion, one hundred forty-three million, three hundred fourteen thousand, four hundred eighty-one".