Base | Representation |
---|---|
bin | 1001001101110001000011… |
… | …1001010001011000110111 |
3 | 1022212121202020221122210002 |
4 | 2103130100321101120313 |
5 | 2312001030443101101 |
6 | 33314343324421515 |
7 | 2064010110021551 |
oct | 223342071213067 |
9 | 38777666848702 |
10 | 10132111300151 |
11 | 325700575a205 |
12 | 11778076a789b |
13 | 5865b9576489 |
14 | 27057ab864d1 |
15 | 12885d301d6b |
hex | 93710e51637 |
10132111300151 has 2 divisors, whose sum is σ = 10132111300152. Its totient is φ = 10132111300150.
The previous prime is 10132111300147. The next prime is 10132111300159. The reversal of 10132111300151 is 15100311123101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10132111300151 - 22 = 10132111300147 is a prime.
It is a super-2 number, since 2×101321113001512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10132111300159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066055650075 + 5066055650076.
It is an arithmetic number, because the mean of its divisors is an integer number (5066055650076).
Almost surely, 210132111300151 is an apocalyptic number.
10132111300151 is a deficient number, since it is larger than the sum of its proper divisors (1).
10132111300151 is an equidigital number, since it uses as much as digits as its factorization.
10132111300151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90, while the sum is 20.
Adding to 10132111300151 its reverse (15100311123101), we get a palindrome (25232422423252).
The spelling of 10132111300151 in words is "ten trillion, one hundred thirty-two billion, one hundred eleven million, three hundred thousand, one hundred fifty-one".
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