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101321311770059 is a prime number
BaseRepresentation
bin10111000010011010110100…
…110010111101010111001011
3111021202020000102112001222212
4113002122310302331113023
5101240022021303120214
6555254211255335335
730225136362652223
oct2702326462752713
9437666012461885
10101321311770059
112a314144064677
12b4448ba38154b
13446c7356143c4
141b03d98989083
15baa8ee6c853e
hex5c26b4cbd5cb

101321311770059 has 2 divisors, whose sum is σ = 101321311770060. Its totient is φ = 101321311770058.

The previous prime is 101321311770011. The next prime is 101321311770061. The reversal of 101321311770059 is 950077113123101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101321311770059 - 212 = 101321311765963 is a prime.

Together with 101321311770061, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101321311769998 and 101321311770025.

It is not a weakly prime, because it can be changed into another prime (101321311770659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50660655885029 + 50660655885030.

It is an arithmetic number, because the mean of its divisors is an integer number (50660655885030).

Almost surely, 2101321311770059 is an apocalyptic number.

101321311770059 is a deficient number, since it is larger than the sum of its proper divisors (1).

101321311770059 is an equidigital number, since it uses as much as digits as its factorization.

101321311770059 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 39690, while the sum is 41.

The spelling of 101321311770059 in words is "one hundred one trillion, three hundred twenty-one billion, three hundred eleven million, seven hundred seventy thousand, fifty-nine".