Base | Representation |
---|---|
bin | 10111000010011010110100… |
… | …110010111101010111001011 |
3 | 111021202020000102112001222212 |
4 | 113002122310302331113023 |
5 | 101240022021303120214 |
6 | 555254211255335335 |
7 | 30225136362652223 |
oct | 2702326462752713 |
9 | 437666012461885 |
10 | 101321311770059 |
11 | 2a314144064677 |
12 | b4448ba38154b |
13 | 446c7356143c4 |
14 | 1b03d98989083 |
15 | baa8ee6c853e |
hex | 5c26b4cbd5cb |
101321311770059 has 2 divisors, whose sum is σ = 101321311770060. Its totient is φ = 101321311770058.
The previous prime is 101321311770011. The next prime is 101321311770061. The reversal of 101321311770059 is 950077113123101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101321311770059 - 212 = 101321311765963 is a prime.
Together with 101321311770061, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 101321311769998 and 101321311770025.
It is not a weakly prime, because it can be changed into another prime (101321311770659) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50660655885029 + 50660655885030.
It is an arithmetic number, because the mean of its divisors is an integer number (50660655885030).
Almost surely, 2101321311770059 is an apocalyptic number.
101321311770059 is a deficient number, since it is larger than the sum of its proper divisors (1).
101321311770059 is an equidigital number, since it uses as much as digits as its factorization.
101321311770059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39690, while the sum is 41.
The spelling of 101321311770059 in words is "one hundred one trillion, three hundred twenty-one billion, three hundred eleven million, seven hundred seventy thousand, fifty-nine".
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