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1013300230001 is a prime number
BaseRepresentation
bin11101011111011010110…
…01100111011101110001
310120212111122011010002012
432233231121213131301
5113100214324330001
62053300444332305
7133131344561543
oct16575531473561
93525448133065
101013300230001
11360813621614
12144474244095
1374727918c17
1437088a05693
151b5592202bb
hexebed667771

1013300230001 has 2 divisors, whose sum is σ = 1013300230002. Its totient is φ = 1013300230000.

The previous prime is 1013300229947. The next prime is 1013300230003. The reversal of 1013300230001 is 1000320033101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1006731289600 + 6568940401 = 1003360^2 + 81049^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1013300230001 is a prime.

It is a super-2 number, since 2×10133002300012 (a number of 25 digits) contains 22 as substring.

Together with 1013300230003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1013300230003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506650115000 + 506650115001.

It is an arithmetic number, because the mean of its divisors is an integer number (506650115001).

Almost surely, 21013300230001 is an apocalyptic number.

It is an amenable number.

1013300230001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013300230001 is an equidigital number, since it uses as much as digits as its factorization.

1013300230001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 1013300230001 its reverse (1000320033101), we get a palindrome (2013620263102).

The spelling of 1013300230001 in words is "one trillion, thirteen billion, three hundred million, two hundred thirty thousand, one".