Base | Representation |
---|---|
bin | 1001001101110100011001… |
… | …1110000010100101100111 |
3 | 1022212201001220021000022202 |
4 | 2103131012132002211213 |
5 | 2312004401043200203 |
6 | 33315012433445115 |
7 | 2064041302661543 |
oct | 223350636024547 |
9 | 38781056230282 |
10 | 10133010131303 |
11 | 3257427063374 |
12 | 1177a1871079b |
13 | 586700850b27 |
14 | 2706242baa23 |
15 | 1288b219c388 |
hex | 93746782967 |
10133010131303 has 2 divisors, whose sum is σ = 10133010131304. Its totient is φ = 10133010131302.
The previous prime is 10133010131269. The next prime is 10133010131339. The reversal of 10133010131303 is 30313101033101.
10133010131303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10133010131303 - 230 = 10131936389479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10133010131203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066505065651 + 5066505065652.
It is an arithmetic number, because the mean of its divisors is an integer number (5066505065652).
Almost surely, 210133010131303 is an apocalyptic number.
10133010131303 is a deficient number, since it is larger than the sum of its proper divisors (1).
10133010131303 is an equidigital number, since it uses as much as digits as its factorization.
10133010131303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 10133010131303 its reverse (30313101033101), we get a palindrome (40446111164404).
The spelling of 10133010131303 in words is "ten trillion, one hundred thirty-three billion, ten million, one hundred thirty-one thousand, three hundred three".
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