Base | Representation |
---|---|
bin | 11101011111011010111… |
… | …01110100000000111101 |
3 | 10120212111201012222222012 |
4 | 32233231131310000331 |
5 | 113100220120024411 |
6 | 2053300524101005 |
7 | 133131360122513 |
oct | 16575535640075 |
9 | 3525451188865 |
10 | 1013301329981 |
11 | 360814202a96 |
12 | 144474694765 |
13 | 74727c127b5 |
14 | 37088c104b3 |
15 | 1b55938b18b |
hex | ebed77403d |
1013301329981 has 2 divisors, whose sum is σ = 1013301329982. Its totient is φ = 1013301329980.
The previous prime is 1013301329969. The next prime is 1013301330011. The reversal of 1013301329981 is 1899231033101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 922817681956 + 90483648025 = 960634^2 + 300805^2 .
It is a cyclic number.
It is not a de Polignac number, because 1013301329981 - 214 = 1013301313597 is a prime.
It is a super-2 number, since 2×10133013299812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1013301320981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506650664990 + 506650664991.
It is an arithmetic number, because the mean of its divisors is an integer number (506650664991).
Almost surely, 21013301329981 is an apocalyptic number.
It is an amenable number.
1013301329981 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013301329981 is an equidigital number, since it uses as much as digits as its factorization.
1013301329981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 41.
The spelling of 1013301329981 in words is "one trillion, thirteen billion, three hundred one million, three hundred twenty-nine thousand, nine hundred eighty-one".
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