Base | Representation |
---|---|
bin | 1001001101110100011111… |
… | …1001110111110011000001 |
3 | 1022212201010120120001100012 |
4 | 2103131013321313303001 |
5 | 2312004423224014403 |
6 | 33315015053434305 |
7 | 2064042014413424 |
oct | 223350771676301 |
9 | 38781116501305 |
10 | 10133034204353 |
11 | 3257439705855 |
12 | 1177a2479b995 |
13 | 58670582c138 |
14 | 2706275859bb |
15 | 1288b4354ed8 |
hex | 93747e77cc1 |
10133034204353 has 2 divisors, whose sum is σ = 10133034204354. Its totient is φ = 10133034204352.
The previous prime is 10133034204343. The next prime is 10133034204407. The reversal of 10133034204353 is 35340243033101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5942366663809 + 4190667540544 = 2437697^2 + 2047112^2 .
It is a cyclic number.
It is not a de Polignac number, because 10133034204353 - 222 = 10133030010049 is a prime.
It is not a weakly prime, because it can be changed into another prime (10133034204313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066517102176 + 5066517102177.
It is an arithmetic number, because the mean of its divisors is an integer number (5066517102177).
Almost surely, 210133034204353 is an apocalyptic number.
It is an amenable number.
10133034204353 is a deficient number, since it is larger than the sum of its proper divisors (1).
10133034204353 is an equidigital number, since it uses as much as digits as its factorization.
10133034204353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38880, while the sum is 32.
Adding to 10133034204353 its reverse (35340243033101), we get a palindrome (45473277237454).
The spelling of 10133034204353 in words is "ten trillion, one hundred thirty-three billion, thirty-four million, two hundred four thousand, three hundred fifty-three".
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