Base | Representation |
---|---|
bin | 1001001101110101001001… |
… | …1100010100100010010101 |
3 | 1022212201120220020120011000 |
4 | 2103131102130110202111 |
5 | 2312010304004212000 |
6 | 33315044411133513 |
7 | 2064046262254413 |
oct | 223352234244225 |
9 | 38781526216130 |
10 | 10133211007125 |
11 | 325751a494348 |
12 | 1177a73a44299 |
13 | 58673335396b |
14 | 270642c4a2b3 |
15 | 1288c4b2b000 |
hex | 93752714895 |
10133211007125 has 64 divisors (see below), whose sum is σ = 18735874560000. Its totient is φ = 5404179211200.
The previous prime is 10133211007097. The next prime is 10133211007159. The reversal of 10133211007125 is 52170011233101.
10133211007125 is a `hidden beast` number, since 101 + 332 + 1 + 100 + 7 + 125 = 666.
It is not a de Polignac number, because 10133211007125 - 29 = 10133211006613 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 156564271 + ... + 156628979.
It is an arithmetic number, because the mean of its divisors is an integer number (292748040000).
Almost surely, 210133211007125 is an apocalyptic number.
10133211007125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
10133211007125 is a deficient number, since it is larger than the sum of its proper divisors (8602663552875).
10133211007125 is an equidigital number, since it uses as much as digits as its factorization.
10133211007125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111132 (or 111116 counting only the distinct ones).
The product of its (nonzero) digits is 1260, while the sum is 27.
The spelling of 10133211007125 in words is "ten trillion, one hundred thirty-three billion, two hundred eleven million, seven thousand, one hundred twenty-five".
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