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10133211312 = 2432737972801
BaseRepresentation
bin10010110111111110…
…01000100010110000
3222011012102110200200
421123333020202300
5131223100230222
64353301515200
7506052606060
oct113377104260
928135373620
1010133211312
11432aa2a704
121b69712b00
13c5648b833
146c1b1b3a0
153e4922eac
hex25bfc88b0

10133211312 has 240 divisors, whose sum is σ = 33641305152. Its totient is φ = 2786918400.

The previous prime is 10133211307. The next prime is 10133211313. The reversal of 10133211312 is 21311233101.

10133211312 is a `hidden beast` number, since 10 + 1 + 332 + 11 + 312 = 666.

10133211312 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×101332113122 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (10133211313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3616312 + ... + 3619112.

Almost surely, 210133211312 is an apocalyptic number.

10133211312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10133211312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16820652576).

10133211312 is an abundant number, since it is smaller than the sum of its proper divisors (23508093840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10133211312 is a wasteful number, since it uses less digits than its factorization.

10133211312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2956 (or 2947 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 10133211312 its reverse (21311233101), we get a palindrome (31444444413).

It can be divided in two parts, 10133 and 211312, that added together give a triangular number (221445 = T665).

The spelling of 10133211312 in words is "ten billion, one hundred thirty-three million, two hundred eleven thousand, three hundred twelve".